\begin{align*}
e^{i\pi} &= e^{\sqrt{-\pi}} \\
         &= e^{-\sqrt\pi} \\
         &= \left(\frac{1}{e}\right)^{\sqrt\pi} \\
         &= \left(\frac{1}{\cancel 3}\right)^\sqrt{\cancel 3} \text{поскольку } e \approx 3 \text{ и } \pi \approx 3 \\
         &= \left(\frac{1}{}\right)^\sqrt{\text{ }} \\
         &= \left(\frac{\text{ }}{\text{ }}\right)\sqrt 1 \\
         &= -1 \\
         &\implies e^{i\pi} = -1 \\
         &\implies e^{i\pi} + 1 = 0 \\
         &\text{ Q.E.D. } \blacksquare
\end{align*}